10y^2-16y=-6

Solution for 10y^2-16y=-6 equation:

10y^2-16y=-6

We move all terms to the left:

10y^2-16y-(-6)=0

We add all the numbers together, and all the variables

10y^2-16y+6=0

a = 10; b = -16; c = +6;
Δ = b2-4ac
Δ = -162-4·10·6
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4}{2*10}=\frac{12}{20}
=3/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4}{2*10}=\frac{20}{20}
=1
$